(3y/2)^2+y^2=13

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Solution for (3y/2)^2+y^2=13 equation: 



(3y/2)^2+y^2=13

We move all terms to the left:

(3y/2)^2+y^2-(13)=0

We add all the numbers together, and all the variables

y^2+(+3y/2)^2-13=0

We multiply all the terms by the denominator


y^2*2)^2+(+3y-13*2)^2=0

We add all the numbers together, and all the variables

y^2*2)^2+(3y-26)^2=0

We add all the numbers together, and all the variables

y^2*2)^2+(3y=0

Wy multiply elements

2y^3=0

We do not support eypression: y^3

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